# 74. Search a 2D Matrix

{% hint style="success" %}
Find possible row, then apply binary search

Consider edge case
{% endhint %}

{% tabs %}
{% tab title="Java" %}

```java
// Some code
class Solution {
    public boolean searchMatrix(int[][] matrix, int target) {
        int row = 0;
        for(; row < matrix.length; row ++) {
            int temp = matrix[row][0];
            if(temp == target)
                return true;
            else if(temp > target)
                break;
        }
        
        row = row == 0? 0: row - 1;
        int left = 0, right = matrix[row].length - 1, temp;
        while(left <= right) {
            int mid = left + (right - left)/2;
            temp = matrix[row][mid];
            if(temp == target)
                return true;
            else if(temp < target)
                left = mid + 1;
            else
                right = mid - 1;
        }
        
        return false;
    }
}
```

{% endtab %}
{% endtabs %}


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